Estimating numbers is a basic concept that students need to learn at the primary level itself. The result of estimation is less accurate and easy to use especially while doing basic arithmetic operations. With the help of the Worksheet on Estimate, you can better understand the principles of Estimation. Practice the Problems in Estimation Worksheet PDF meticulously and solve problems fastly in your exams. 6th Grade Math Students can enhance their math skills by answering the questions from the Estimation Worksheets PDF.

Problem 1:
Estimate the following numbers to nearest Tens,

(i) 8
(ii) 24
(iii) 96
(iv) 729

Solution:

Given in the question the values are,
Now, we have to round the Nearest Tens of given values.
(i) 8
The value is 8, 8 is greater than 5. So, we have to replace zero units place and increase 1 by tens place.
So, the value is 08.
After replacing the value is 10.
(ii) 24
The given value is 24, 4 is less than 5. Now, we have to replace zero in the unit’s place.
So, the estimated tens value is 24.
After replacing 0, the value is 20.
(iii) 96
The value 96 has 6 is greater than 5. So, replace 6 with zero in the unit’s place and increase by 1 in one’s place.
So, the tens value is 96.
After replacing units place and increasing one’s place, the value is 100.
Thus, the value is 100.
(iv) 729
The value 729 has 9 is greater than 5. So, replace 9 with zero in the unit’s place and increase by 1 in one’s place.
So, the value is 729.
After replacing units place and increasing one’s place, the value is 730.
Therefore, the estimated tens value is 730.

Problem 2:
Estimate to the nearest Hundreds,
(i) 678
(ii) 3640
(iii)945154

Solution:

In the question, the values are given
Now, we have to round off the nearest hundreds of the values.
(i)678
The value is 678, ten’s place digit is 7 means that is greater than 5. So, we have to replace the ten’s place digit and units place digit with 0 and increase hundreds place digit by 1.
So, after replacing digits the value is 700.
Therefore, 678 estimate to nearest 100 is 700.

(ii) The number is 3640
We can see that the digit in tens place is 4 which is less than 5. So, we have to replace the ten’s place and units place digits with 0 and write the remaining digits as it is.
So, after replacing digits the value is 3600.
Thus, 3640 is estimating nearest to 100 is 3600.

(iii)945154
Now, we can see that the digit in tens place is 5 which is equal to 5. So, we have to replace the ten’s place and units place digits with 0 and increase the hundred place digit by one.
So, after replacing digits the value is 945200
Thus, 945154 is estimating nearest to 100 is 945200.

Problem 3:
What is the value of the Estimate to the nearest 1000,

(i) 8912
(ii) 473178

Solution:

Given the values, find the nearest 1000 value.
(i) 8912
The value is 8912, hundred’s place digit is 9 means that is greater than 5. So, we have to replace the hundreds place digit, ten’s place digit, and units place digit with 0 and increase the thousands place digit by 1.
So, after replacing digits the value is 9000.
Therefore, 8912 is estimated to nearest 1000’s is 9000.
(ii) The number is 473178
Now, we can see that the digit in hundreds place is 1 which is less than 5. So, we have to replace the hundreds place, tens place, units place digits with 0 and keep the remaining values as it is.
So, after replacing digits the value is 473000.
Thus, 473178 is estimating nearest to 1000 is 473000.

Problem 4:
Estimate the sum 812 and 752 to the nearest hundred. What is the final sum value?

Solution:

As given in the question, the values are 812, 752
Now, we have to find out the estimated sum hundreds value.
The number is 812, in this tens place digit is 1 which is less than 5. So we have to replace zero in units place digit and tens place digit, remaining digits as it is.
So, after replacing the digit, the value is 800.
Next, the number is 752. In this tens place digit 5 which is equal to 5. So, we need to put zeros in the units place digit, tens place digit, and increase 1 by hundreds place digit.
After performing the operation, the value is 800.
The nearest hundreds value of 812, 752 is 800, 800.
Now, find the sum value,
800 + 800 = 1600
Now check if the estimated answer is closer to the actual answer.
812 + 752 = 1564
1564 is closer to 1600.
Thus the final sum value is 1600.

Problem 5:
What is the estimating difference tens value of 421 and 120

Solution:

Given the values 421 and 120
Now, find the estimated difference tens value.
The number is 421, in this unit place digit is 1, which is less than 5. So, replace units place by zero and the remaining digits as it is.
Then the value is 420.
Next, the number is 120. This value will be in the nearest tens value. So, we need not change it.
So, the given values in the nearest tens are 420, 120.
Estimated Difference is 420 – 120 = 300
Thus, the estimating tens difference value of given numbers is 300.

Problem 6:
What is the Estimated Sum value of 52, 94?

Solution:

Given the values 52 and 94
Now, we have to round off the numbers to the nearest 10. Next, find the estimated sum value.
So, the values nearest 10 is,
In 52, 2 is less than 5. So, replace 0 in the unit’s place digit. Next, the value is 94, in this 4 is less than 5. So place zero in the units place digit.
The tens values are 50, 90.
50 + 90 = 140
Hence, the estimated sum value is 140.

Problem 7:
A shopkeeper has 81 packets of chocolates. If each packet has 27 chocolates, then how many chocolates are there in the shop?

(i) 3600 (ii) 2400

Solution:

In the question, the given numbers are 81 and 27.
Now, we will Round off the given numbers to the nearest tens, hundreds, or thousands.
First, the value is 81 it is between 80 and 90. But the 81 is near to 80 compared to 90. Therefore, 81 is rounded down to 80.
Next, the value is 27, it is between 20 and 30. But the 27 is near to 30 compared to 20. Therefore, 27 is rounded up to 30.
Multiply 80 and 30.
80 × 30 = 2400.
Therefore, the estimated product is 2400. Hence, Option (ii) 2400 is correct.

Problem 8:
A school track is 13.96 meters wide. It is divided into 7 lanes of equal width. How wide is each lane?

Solution:

In the given question, the data is given.
The width of each lane is nothing but the quotient when we divide 13.96 by 7.
Now, the Round off the school track to the nearest 10 i.e 13.96 is 14.00.
Divide 14 by 7
14 ÷ 7= 2
So, Approximately, 2 meters wide of each lane.

Problem 9:
A museum has 318 marble jars. Each jar has 129 marbles. Find the total number of marbles in jars in the museum?

Solution:

In the given question, the data is
First, the given numbers are 318 and 129.
Now, we need to Round off the given numbers to the nearest tens, hundreds, or thousands.
Next, take the values. The value 318 is between 300 and 400. But the 318 is near to 300 compared to 400. Therefore, 318 is rounded down to 300.
The value 129 is between 100 and 200. But the 129 is near to 100 compared to 200. Therefore, 129 is rounded up to 100.
Multiply 300 and 100.
300 × 100 = 30,000.
So, the estimated product is 30,000.
Therefore, the total number of marbles in the museum is 30,000.

Problem 10:
Estimate the sum of 59, 69, 48.

Solution:

Given the values are 59, 69, 48.
Now, we need to find out the estimated sum value.
First, take 59, 9 is greater than 5, so you can add 1 to the tens place value and 0 to the unit place value, then the value is 60.
The number 59 nearest to ten is 60. Likewise remaining values.
The number 69 nearest to ten is 70
The number 48 nearest to ten is 50
Now add the three nearest tens numbers 60 + 70 + 50 = 180
Now check whether the estimated answer is closer to the actual answer.
59 + 69 + 48 = 176
6 is greater than 5, so you can add 1 to the tens place value and 0 to the unit place value.
176 nearest to 10 is 180.
Thus, the given three numbers estimated sum value is 180.